Given log3=0.4772, log7=0.8451, log5=0.6990, log2=0.3010, how do you Write 2 log 3 + 3 log 5 Log 3 a
23. Write each logarithm in terms of log3 and log5: a) log 45, b) log
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Answered: 2log5(x-3) - log5(8) = log5(2) | bartleby
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